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\frac{\left(1\times 2+1\right)\times 2}{2\left(4\times 2+1\right)}
Divide \frac{1\times 2+1}{2} by \frac{4\times 2+1}{2} by multiplying \frac{1\times 2+1}{2} by the reciprocal of \frac{4\times 2+1}{2}.
\frac{1+2}{1+2\times 4}
Cancel out 2 in both numerator and denominator.
\frac{3}{1+2\times 4}
Add 1 and 2 to get 3.
\frac{3}{1+8}
Multiply 2 and 4 to get 8.
\frac{3}{9}
Add 1 and 8 to get 9.
\frac{1}{3}
Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.