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\frac{\left(1\times 2+1\right)\times 4}{2\left(3\times 4+3\right)}
Divide \frac{1\times 2+1}{2} by \frac{3\times 4+3}{4} by multiplying \frac{1\times 2+1}{2} by the reciprocal of \frac{3\times 4+3}{4}.
\frac{2\left(1+2\right)}{3+3\times 4}
Cancel out 2 in both numerator and denominator.
\frac{2\times 3}{3+3\times 4}
Add 1 and 2 to get 3.
\frac{6}{3+3\times 4}
Multiply 2 and 3 to get 6.
\frac{6}{3+12}
Multiply 3 and 4 to get 12.
\frac{6}{15}
Add 3 and 12 to get 15.
\frac{2}{5}
Reduce the fraction \frac{6}{15} to lowest terms by extracting and canceling out 3.