Solve 1div8+1/8=1/16+x

$$1 \div 8 + \frac { 1 } { 8 } = \frac { 1 } { 16 } + x$$

Solve for x

$$x=\frac{3}{16}=0.1875$$

Steps for Solving Linear Equation

Since \frac{1}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{1+1}{8}=\frac{1}{16}+x$$

Add 1 and 1 to get 2.

$$\frac{2}{8}=\frac{1}{16}+x$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{1}{4}=\frac{1}{16}+x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{16}+x=\frac{1}{4}$$

Subtract \frac{1}{16} from both sides.

$$x=\frac{1}{4}-\frac{1}{16}$$

Least common multiple of 4 and 16 is 16. Convert \frac{1}{4} and \frac{1}{16} to fractions with denominator 16.

$$x=\frac{4}{16}-\frac{1}{16}$$

Since \frac{4}{16} and \frac{1}{16} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{4-1}{16}$$

Subtract 1 from 4 to get 3.

$$x=\frac{3}{16}$$