Solve 1div2+3(1div3-1

$$1 \div 2+3(1 \div 3-1$$

Evaluate

$$-\frac{3}{2}=-1.5$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$\frac{1}{2}+3\left(\frac{1}{3}-\frac{3}{3}\right)$$

Since \frac{1}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{2}+3\times \frac{1-3}{3}$$

Subtract 3 from 1 to get -2.

$$\frac{1}{2}+3\left(-\frac{2}{3}\right)$$

Cancel out 3 and 3.

$$\frac{1}{2}-2$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{1}{2}-\frac{4}{2}$$

Since \frac{1}{2} and \frac{4}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-4}{2}$$

Subtract 4 from 1 to get -3.

$$-\frac{3}{2}$$

Factor

$$-\frac{3}{2} = -1\frac{1}{2} = -1.5$$