Solve 1div2*x+4+x(-4-2)+-3(2-x)=0

$$1 \div 2 \times x+4+x(-4-2)+-3(2-x)=0$$

Solve for x

$$x=-\frac{4}{5}=-0.8$$

Steps for Solving Linear Equation

Subtract 2 from -4 to get -6.

$$\frac{1}{2}x+4+x\left(-6\right)-3\left(2-x\right)=0$$

Combine \frac{1}{2}x and x\left(-6\right) to get -\frac{11}{2}x.

$$-\frac{11}{2}x+4-3\left(2-x\right)=0$$

Use the distributive property to multiply -3 by 2-x.

$$-\frac{11}{2}x+4-6+3x=0$$

Subtract 6 from 4 to get -2.

$$-\frac{11}{2}x-2+3x=0$$

Combine -\frac{11}{2}x and 3x to get -\frac{5}{2}x.

$$-\frac{5}{2}x-2=0$$

Add 2 to both sides. Anything plus zero gives itself.

$$-\frac{5}{2}x=2$$

Multiply both sides by -\frac{2}{5}, the reciprocal of -\frac{5}{2}.

$$x=2\left(-\frac{2}{5}\right)$$

Express 2\left(-\frac{2}{5}\right) as a single fraction.

$$x=\frac{2\left(-2\right)}{5}$$

Multiply 2 and -2 to get -4.

$$x=\frac{-4}{5}$$

Fraction \frac{-4}{5} can be rewritten as -\frac{4}{5} by extracting the negative sign.

$$x=-\frac{4}{5}$$