Solve 1*x^2+5x-(x^2+x-6)=0

$$1 \cdot x ^ { 2 } + 5 x - ( x ^ { 2 } + x - 6 ) = 0$$

Solve for x

$$x = -\frac{3}{2} = -1\frac{1}{2} = -1.5$$

Steps for Solving Linear Equation

To find the opposite of x^{2}+x-6, find the opposite of each term.

$$1x^{2}+5x-x^{2}-x+6=0$$

Combine 1x^{2} and -x^{2} to get 0.

$$5x-x+6=0$$

Combine 5x and -x to get 4x.

$$4x+6=0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$4x=-6$$

Divide both sides by 4.

$$x=\frac{-6}{4}$$

Reduce the fraction \frac{-6}{4} to lowest terms by extracting and canceling out 2.

$$x=-\frac{3}{2}$$