Solve 1*(-101/6)+(-71/5)-(-111/4)

$$1 \cdot ( - 10 \frac { 1 } { 6 } ) + ( - 7 \frac { 1 } { 5 } ) - ( - 11 \frac { 1 } { 4 } )$$

Evaluate

$$-\frac{367}{60}\approx -6.116666667$$

Solution Steps

Multiply 10 and 6 to get 60.

$$1\left(-\frac{60+1}{6}\right)-\frac{7\times 5+1}{5}-\left(-\frac{11\times 4+1}{4}\right)$$

Add 60 and 1 to get 61.

$$1\left(-\frac{61}{6}\right)-\frac{7\times 5+1}{5}-\left(-\frac{11\times 4+1}{4}\right)$$

Multiply 1 and -\frac{61}{6} to get -\frac{61}{6}.

$$-\frac{61}{6}-\frac{7\times 5+1}{5}-\left(-\frac{11\times 4+1}{4}\right)$$

Multiply 7 and 5 to get 35.

$$-\frac{61}{6}-\frac{35+1}{5}-\left(-\frac{11\times 4+1}{4}\right)$$

Add 35 and 1 to get 36.

$$-\frac{61}{6}-\frac{36}{5}-\left(-\frac{11\times 4+1}{4}\right)$$

Least common multiple of 6 and 5 is 30. Convert -\frac{61}{6} and \frac{36}{5} to fractions with denominator 30.

$$-\frac{305}{30}-\frac{216}{30}-\left(-\frac{11\times 4+1}{4}\right)$$

Since -\frac{305}{30} and \frac{216}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-305-216}{30}-\left(-\frac{11\times 4+1}{4}\right)$$

Subtract 216 from -305 to get -521.

$$-\frac{521}{30}-\left(-\frac{11\times 4+1}{4}\right)$$

Multiply 11 and 4 to get 44.

$$-\frac{521}{30}-\left(-\frac{44+1}{4}\right)$$

Add 44 and 1 to get 45.

$$-\frac{521}{30}-\left(-\frac{45}{4}\right)$$

The opposite of -\frac{45}{4} is \frac{45}{4}.

$$-\frac{521}{30}+\frac{45}{4}$$

Least common multiple of 30 and 4 is 60. Convert -\frac{521}{30} and \frac{45}{4} to fractions with denominator 60.

$$-\frac{1042}{60}+\frac{675}{60}$$

Since -\frac{1042}{60} and \frac{675}{60} have the same denominator, add them by adding their numerators.

$$\frac{-1042+675}{60}$$

Add -1042 and 675 to get -367.

$$-\frac{367}{60}$$

Factor

$$-\frac{367}{60} = -6\frac{7}{60} = -6.116666666666666$$