Solve 1^{4}+(-2)^{1/1}-(-2)^3+1^2+32^0+8*2^2

$$1 ^ { 4 } + ( - 2 ) ^ { 1 / 1 } - ( - 2 ) ^ { 3 } + 1 ^ { 2 } + 32 ^ { 0 } + 8 \cdot 2 ^ { 2 }$$

Evaluate

$$41$$

Solution Steps

Divide 1 by 1 to get 1.

$$1^{4}+\left(-2\right)^{1}-\left(-2\right)^{3}+1^{2}+32^{0}+8\times 2^{2}$$

Calculate 1 to the power of 4 and get 1.

$$1+\left(-2\right)^{1}-\left(-2\right)^{3}+1^{2}+32^{0}+8\times 2^{2}$$

Calculate -2 to the power of 1 and get -2.

$$1-2-\left(-2\right)^{3}+1^{2}+32^{0}+8\times 2^{2}$$

Subtract 2 from 1 to get -1.

$$-1-\left(-2\right)^{3}+1^{2}+32^{0}+8\times 2^{2}$$

Calculate -2 to the power of 3 and get -8.

$$-1-\left(-8\right)+1^{2}+32^{0}+8\times 2^{2}$$

The opposite of -8 is 8.

$$-1+8+1^{2}+32^{0}+8\times 2^{2}$$

Add -1 and 8 to get 7.

$$7+1^{2}+32^{0}+8\times 2^{2}$$

Calculate 1 to the power of 2 and get 1.

$$7+1+32^{0}+8\times 2^{2}$$

Add 7 and 1 to get 8.

$$8+32^{0}+8\times 2^{2}$$

Calculate 32 to the power of 0 and get 1.

$$8+1+8\times 2^{2}$$

Add 8 and 1 to get 9.

$$9+8\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$9+8\times 4$$

Multiply 8 and 4 to get 32.

$$9+32$$

Add 9 and 32 to get 41.

$$41$$

Factor

$$41$$