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1+\frac{\frac{1}{6}\left(|-2|-\left(-3\right)^{3}-\left(-2\right)^{2}\right)}{\left(-\frac{5}{2}\right)^{2}}
Calculate 1 to the power of 4 and get 1.
1+\frac{\frac{1}{6}\left(2-\left(-3\right)^{3}-\left(-2\right)^{2}\right)}{\left(-\frac{5}{2}\right)^{2}}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -2 is 2.
1+\frac{\frac{1}{6}\left(2-\left(-27\right)-\left(-2\right)^{2}\right)}{\left(-\frac{5}{2}\right)^{2}}
Calculate -3 to the power of 3 and get -27.
1+\frac{\frac{1}{6}\left(2+27-\left(-2\right)^{2}\right)}{\left(-\frac{5}{2}\right)^{2}}
The opposite of -27 is 27.
1+\frac{\frac{1}{6}\left(29-\left(-2\right)^{2}\right)}{\left(-\frac{5}{2}\right)^{2}}
Add 2 and 27 to get 29.
1+\frac{\frac{1}{6}\left(29-4\right)}{\left(-\frac{5}{2}\right)^{2}}
Calculate -2 to the power of 2 and get 4.
1+\frac{\frac{1}{6}\times 25}{\left(-\frac{5}{2}\right)^{2}}
Subtract 4 from 29 to get 25.
1+\frac{\frac{25}{6}}{\left(-\frac{5}{2}\right)^{2}}
Multiply \frac{1}{6} and 25 to get \frac{25}{6}.
1+\frac{\frac{25}{6}}{\frac{25}{4}}
Calculate -\frac{5}{2} to the power of 2 and get \frac{25}{4}.
1+\frac{25}{6}\times \frac{4}{25}
Divide \frac{25}{6} by \frac{25}{4} by multiplying \frac{25}{6} by the reciprocal of \frac{25}{4}.
1+\frac{25\times 4}{6\times 25}
Multiply \frac{25}{6} times \frac{4}{25} by multiplying numerator times numerator and denominator times denominator.
1+\frac{4}{6}
Cancel out 25 in both numerator and denominator.
1+\frac{2}{3}
Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.
\frac{3}{3}+\frac{2}{3}
Convert 1 to fraction \frac{3}{3}.
\frac{3+2}{3}
Since \frac{3}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.
\frac{5}{3}
Add 3 and 2 to get 5.