Solve 1^2-4(-32/4900)(190)

$$1 ^ { 2 } - 4 ( - \frac { 32 } { 4900 } ) ( 190 )$$

Evaluate

$$\frac{1461}{245}\approx 5.963265306$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$1-4\left(-\frac{32}{4900}\right)\times 190$$

Reduce the fraction \frac{32}{4900} to lowest terms by extracting and canceling out 4.

$$1-4\left(-\frac{8}{1225}\right)\times 190$$

Express 4\left(-\frac{8}{1225}\right) as a single fraction.

$$1-\frac{4\left(-8\right)}{1225}\times 190$$

Multiply 4 and -8 to get -32.

$$1-\frac{-32}{1225}\times 190$$

Fraction \frac{-32}{1225} can be rewritten as -\frac{32}{1225} by extracting the negative sign.

$$1-\left(-\frac{32}{1225}\times 190\right)$$

Express -\frac{32}{1225}\times 190 as a single fraction.

$$1-\frac{-32\times 190}{1225}$$

Multiply -32 and 190 to get -6080.

$$1-\frac{-6080}{1225}$$

Reduce the fraction \frac{-6080}{1225} to lowest terms by extracting and canceling out 5.

$$1-\left(-\frac{1216}{245}\right)$$

The opposite of -\frac{1216}{245} is \frac{1216}{245}.

$$1+\frac{1216}{245}$$

Convert 1 to fraction \frac{245}{245}.

$$\frac{245}{245}+\frac{1216}{245}$$

Since \frac{245}{245} and \frac{1216}{245} have the same denominator, add them by adding their numerators.

$$\frac{245+1216}{245}$$

Add 245 and 1216 to get 1461.

$$\frac{1461}{245}$$

Factor

$$\frac{3 \cdot 487}{5 \cdot 7 ^ {2}} = 5\frac{236}{245} = 5.963265306122449$$