Solve 1^2-4(-32/3025)(190)

$$1 ^ { 2 } - 4 ( - \frac { 32 } { 3025 } ) ( 190 )$$

Evaluate

$$\frac{5469}{605}\approx 9.039669421$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$1-4\left(-\frac{32}{3025}\right)\times 190$$

Express 4\left(-\frac{32}{3025}\right) as a single fraction.

$$1-\frac{4\left(-32\right)}{3025}\times 190$$

Multiply 4 and -32 to get -128.

$$1-\frac{-128}{3025}\times 190$$

Fraction \frac{-128}{3025} can be rewritten as -\frac{128}{3025} by extracting the negative sign.

$$1-\left(-\frac{128}{3025}\times 190\right)$$

Express -\frac{128}{3025}\times 190 as a single fraction.

$$1-\frac{-128\times 190}{3025}$$

Multiply -128 and 190 to get -24320.

$$1-\frac{-24320}{3025}$$

Reduce the fraction \frac{-24320}{3025} to lowest terms by extracting and canceling out 5.

$$1-\left(-\frac{4864}{605}\right)$$

The opposite of -\frac{4864}{605} is \frac{4864}{605}.

$$1+\frac{4864}{605}$$

Convert 1 to fraction \frac{605}{605}.

$$\frac{605}{605}+\frac{4864}{605}$$

Since \frac{605}{605} and \frac{4864}{605} have the same denominator, add them by adding their numerators.

$$\frac{605+4864}{605}$$

Add 605 and 4864 to get 5469.

$$\frac{5469}{605}$$

Factor

$$\frac{3 \cdot 1823}{5 \cdot 11 ^ {2}} = 9\frac{24}{605} = 9.039669421487604$$