Solve 1^{2}+2^{2}+3^2+4^2+5^2+6^2

$$1 ^ { 2 } + 2 ^ { 2 } + 3 ^ { 2 } + 4 ^ { 2 } + 5 ^ { 2 } + 6 ^ { 2 }$$

Evaluate

$$91$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$1+2^{2}+3^{2}+4^{2}+5^{2}+6^{2}$$

Calculate 2 to the power of 2 and get 4.

$$1+4+3^{2}+4^{2}+5^{2}+6^{2}$$

Add 1 and 4 to get 5.

$$5+3^{2}+4^{2}+5^{2}+6^{2}$$

Calculate 3 to the power of 2 and get 9.

$$5+9+4^{2}+5^{2}+6^{2}$$

Add 5 and 9 to get 14.

$$14+4^{2}+5^{2}+6^{2}$$

Calculate 4 to the power of 2 and get 16.

$$14+16+5^{2}+6^{2}$$

Add 14 and 16 to get 30.

$$30+5^{2}+6^{2}$$

Calculate 5 to the power of 2 and get 25.

$$30+25+6^{2}$$

Add 30 and 25 to get 55.

$$55+6^{2}$$

Calculate 6 to the power of 2 and get 36.

$$55+36$$

Add 55 and 36 to get 91.

$$91$$

Factor

$$7\times 13$$