Solve 1^{2}+(1^{2}+2^2)+(1^2+2^2+3^2)

$$1 ^ { 2 } + ( 1 ^ { 2 } + 2 ^ { 2 } ) + ( 1 ^ { 2 } + 2 ^ { 2 } + 3 ^ { 2 } )$$

Evaluate

$$20$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$1+1^{2}+2^{2}+1^{2}+2^{2}+3^{2}$$

Calculate 1 to the power of 2 and get 1.

$$1+1+2^{2}+1^{2}+2^{2}+3^{2}$$

Add 1 and 1 to get 2.

$$2+2^{2}+1^{2}+2^{2}+3^{2}$$

Calculate 2 to the power of 2 and get 4.

$$2+4+1^{2}+2^{2}+3^{2}$$

Add 2 and 4 to get 6.

$$6+1^{2}+2^{2}+3^{2}$$

Calculate 1 to the power of 2 and get 1.

$$6+1+2^{2}+3^{2}$$

Add 6 and 1 to get 7.

$$7+2^{2}+3^{2}$$

Calculate 2 to the power of 2 and get 4.

$$7+4+3^{2}$$

Add 7 and 4 to get 11.

$$11+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$11+9$$

Add 11 and 9 to get 20.

$$20$$

Factor

$$2^{2}\times 5$$