Solve 1=sqrt{4y+16}-1

$$1 = \sqrt { 4 y + 16 } - 1$$

Solve for y

$$y=-3$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{4y+16}-1=1$$

Add 1 to both sides.

$$\sqrt{4y+16}=1+1$$

Add 1 and 1 to get 2.

$$\sqrt{4y+16}=2$$

Square both sides of the equation.

$$4y+16=4$$

Subtract 16 from both sides of the equation.

$$4y+16-16=4-16$$

Subtracting 16 from itself leaves 0.

$$4y=4-16$$

Subtract 16 from 4.

$$4y=-12$$

Divide both sides by 4.

$$\frac{4y}{4}=-\frac{12}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=-\frac{12}{4}$$

Divide -12 by 4.

$$y=-3$$