Solve 1:x-5-12x+1+x-8

$$1 : x - 5 - 12 x + 1 + x - 8$$

Evaluate

$$-11x-12+\frac{1}{x}$$

Short Solution Steps

Add -5 and 1 to get -4.

$$\frac{1}{x}-4-12x+x-8$$

Combine -12x and x to get -11x.

$$\frac{1}{x}-4-11x-8$$

Subtract 8 from -4 to get -12.

$$\frac{1}{x}-12-11x$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -12-11x times \frac{x}{x}.

$$\frac{1}{x}+\frac{\left(-12-11x\right)x}{x}$$

Since \frac{1}{x} and \frac{\left(-12-11x\right)x}{x} have the same denominator, add them by adding their numerators.

$$\frac{1+\left(-12-11x\right)x}{x}$$

Do the multiplications in 1+\left(-12-11x\right)x.

$$\frac{1-12x-11x^{2}}{x}$$

Factor

$$-\frac{11\left(x-\frac{-\sqrt{47}-6}{11}\right)\left(x-\frac{\sqrt{47}-6}{11}\right)}{x}$$