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\left(5x+1\right)\times 1x=f
Variable f cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by f\left(5x+1\right), the least common multiple of f,1+5x.
\left(5x+1\right)x=f
Use the distributive property to multiply 5x+1 by 1.
5x^{2}+x=f
Use the distributive property to multiply 5x+1 by x.
f=5x^{2}+x
Swap sides so that all variable terms are on the left hand side.
f=5x^{2}+x\text{, }f\neq 0
Variable f cannot be equal to 0.