Solve 1/1^3-C(1/2)^2quad2(1/2)-3

$$1 / 1 ^ { 3 } - C ( 1 / 2 ) ^ { 2 } \quad 2 ( 1 / 2 ) - 3$$

Evaluate

$$-\frac{C}{4}-2$$

Solution Steps

Divide 1 by 1 to get 1.

$$1^{3}-C\times \left(\frac{1}{2}\right)^{2}\times 2\times \frac{1}{2}-3$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$1^{3}-C\times \left(\frac{1}{2}\right)^{3}\times 2-3$$

Calculate 1 to the power of 3 and get 1.

$$1-C\times \left(\frac{1}{2}\right)^{3}\times 2-3$$

Calculate \frac{1}{2} to the power of 3 and get \frac{1}{8}.

$$1-C\times \frac{1}{8}\times 2-3$$

Multiply \frac{1}{8} and 2 to get \frac{1}{4}.

$$1-C\times \frac{1}{4}-3$$

Multiply -1 and \frac{1}{4} to get -\frac{1}{4}.

$$1-\frac{1}{4}C-3$$

Subtract 3 from 1 to get -2.

$$-2-\frac{1}{4}C$$

Factor

$$\frac{-C-8}{4}$$

Solution Steps

Factor out \frac{1}{4}.

$$\frac{-8-C}{4}$$

Consider 4-C-12. Multiply and combine like terms.

$$-C-8$$

Rewrite the complete factored expression.

$$\frac{-C-8}{4}$$