Solve 1/(2^5+2^8)^5*2^-5quad[b]

$$1 / ( 2 ^ { 5 } + 2 ^ { 8 } ) ^ { 5 } \times 2 ^ { - 5 } \quad [ b ]$$

Evaluate

$$\frac{b}{63403380965376}$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$\frac{1}{\left(32+2^{8}\right)^{5}}\times 2^{-5}b$$

Calculate 2 to the power of 8 and get 256.

$$\frac{1}{\left(32+256\right)^{5}}\times 2^{-5}b$$

Add 32 and 256 to get 288.

$$\frac{1}{288^{5}}\times 2^{-5}b$$

Calculate 288 to the power of 5 and get 1981355655168.

$$\frac{1}{1981355655168}\times 2^{-5}b$$

Calculate 2 to the power of -5 and get \frac{1}{32}.

$$\frac{1}{1981355655168}\times \frac{1}{32}b$$

Multiply \frac{1}{1981355655168} and \frac{1}{32} to get \frac{1}{63403380965376}.

$$\frac{1}{63403380965376}b$$

Expand

$$\frac{b}{63403380965376}$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$\frac{1}{\left(32+2^{8}\right)^{5}}\times 2^{-5}b$$

Calculate 2 to the power of 8 and get 256.

$$\frac{1}{\left(32+256\right)^{5}}\times 2^{-5}b$$

Add 32 and 256 to get 288.

$$\frac{1}{288^{5}}\times 2^{-5}b$$

Calculate 288 to the power of 5 and get 1981355655168.

$$\frac{1}{1981355655168}\times 2^{-5}b$$

Calculate 2 to the power of -5 and get \frac{1}{32}.

$$\frac{1}{1981355655168}\times \frac{1}{32}b$$

Multiply \frac{1}{1981355655168} and \frac{1}{32} to get \frac{1}{63403380965376}.

$$\frac{1}{63403380965376}b$$