Solve 1,8/9*(3/4-(7/16-25)0)

$$1 , \frac { 8 } { 9 } \times ( \frac { 3 } { 4 } - ( \frac { 7 } { 16 } - 25 ) 0 )$$

Sort

$$\frac{2}{3},1$$

Solution Steps

Convert 25 to fraction \frac{400}{16}.

$$sort(1,\frac{8}{9}\left(\frac{3}{4}-\left(\frac{7}{16}-\frac{400}{16}\right)\times 0\right))$$

Since \frac{7}{16} and \frac{400}{16} have the same denominator, subtract them by subtracting their numerators.

$$sort(1,\frac{8}{9}\left(\frac{3}{4}-\frac{7-400}{16}\times 0\right))$$

Subtract 400 from 7 to get -393.

$$sort(1,\frac{8}{9}\left(\frac{3}{4}-\left(-\frac{393}{16}\times 0\right)\right))$$

Multiply -\frac{393}{16} and 0 to get 0.

$$sort(1,\frac{8}{9}\left(\frac{3}{4}-0\right))$$

Subtract 0 from \frac{3}{4} to get \frac{3}{4}.

$$sort(1,\frac{8}{9}\times \frac{3}{4})$$

Multiply \frac{8}{9} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$sort(1,\frac{8\times 3}{9\times 4})$$

Do the multiplications in the fraction \frac{8\times 3}{9\times 4}.

$$sort(1,\frac{24}{36})$$

Reduce the fraction \frac{24}{36} to lowest terms by extracting and canceling out 12.

$$sort(1,\frac{2}{3})$$

Convert decimal numbers in the list 1,\frac{2}{3} to fractions.

$$1,\frac{2}{3}$$

To sort the list, start from a single element 1.

$$1$$

Insert \frac{2}{3} to the appropriate location in the new list.

$$\frac{2}{3},1$$

Evaluate

$$1,\frac{2}{3}$$