Solve 1+zzx-zzy=0

$$1 + z z x - z z y = 0$$

Solve for x

$$x=y-\frac{1}{z^{2}}$$

$$z\neq 0$$

Steps for Solving Linear Equation

Multiply z and z to get z^{2}.

$$1+z^{2}x-zzy=0$$

Multiply z and z to get z^{2}.

$$1+z^{2}x-z^{2}y=0$$

Add z^{2}y to both sides.

$$1+z^{2}x=0+z^{2}y$$

Anything plus zero gives itself.

$$1+z^{2}x=z^{2}y$$

Subtract 1 from both sides.

$$z^{2}x=z^{2}y-1$$

The equation is in standard form.

$$z^{2}x=yz^{2}-1$$

Divide both sides by z^{2}.

$$\frac{z^{2}x}{z^{2}}=\frac{yz^{2}-1}{z^{2}}$$

Dividing by z^{2} undoes the multiplication by z^{2}.

$$x=\frac{yz^{2}-1}{z^{2}}$$

Divide z^{2}y-1 by z^{2}.

$$x=y-\frac{1}{z^{2}}$$

Solve for y

$$y=x+\frac{1}{z^{2}}$$

$$z\neq 0$$

Steps for Solving Linear Equation

Multiply z and z to get z^{2}.

$$1+z^{2}x-zzy=0$$

Multiply z and z to get z^{2}.

$$1+z^{2}x-z^{2}y=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$z^{2}x-z^{2}y=-1$$

Subtract z^{2}x from both sides.

$$-z^{2}y=-1-z^{2}x$$

The equation is in standard form.

$$\left(-z^{2}\right)y=-xz^{2}-1$$

Divide both sides by -z^{2}.

$$\frac{\left(-z^{2}\right)y}{-z^{2}}=\frac{-xz^{2}-1}{-z^{2}}$$

Dividing by -z^{2} undoes the multiplication by -z^{2}.

$$y=\frac{-xz^{2}-1}{-z^{2}}$$

Divide -1-z^{2}x by -z^{2}.

$$y=x+\frac{1}{z^{2}}$$