Solve 1+x=(1+6.375%/12)^12

$$1 + x = ( 1 + \frac { 6.375 \% } { 12 } ) ^ { 12 }$$

Solve for x

$$x=0.065646078190780609270600259256282975412755999189418076866786577738821506500244140625$$

Steps for Solving Linear Equation

Expand \frac{6.375}{100} by multiplying both numerator and the denominator by 1000.

$$1+x=\left(1+\frac{\frac{6375}{100000}}{12}\right)^{12}$$

Reduce the fraction \frac{6375}{100000} to lowest terms by extracting and canceling out 125.

$$1+x=\left(1+\frac{\frac{51}{800}}{12}\right)^{12}$$

Express \frac{\frac{51}{800}}{12} as a single fraction.

$$1+x=\left(1+\frac{51}{800\times 12}\right)^{12}$$

Multiply 800 and 12 to get 9600.

$$1+x=\left(1+\frac{51}{9600}\right)^{12}$$

Reduce the fraction \frac{51}{9600} to lowest terms by extracting and canceling out 3.

$$1+x=\left(1+\frac{17}{3200}\right)^{12}$$

Add 1 and \frac{17}{3200} to get \frac{3217}{3200}.

$$1+x=\left(\frac{3217}{3200}\right)^{12}$$

Calculate \frac{3217}{3200} to the power of 12 and get \frac{1228606279846100479010631557699845022496961}{1152921504606846976000000000000000000000000}.

$$1+x=\frac{1228606279846100479010631557699845022496961}{1152921504606846976000000000000000000000000}$$

Subtract 1 from both sides.

$$x=\frac{1228606279846100479010631557699845022496961}{1152921504606846976000000000000000000000000}-1$$

Subtract 1 from \frac{1228606279846100479010631557699845022496961}{1152921504606846976000000000000000000000000} to get \frac{75684775239253503010631557699845022496961}{1152921504606846976000000000000000000000000}.

$$x=\frac{75684775239253503010631557699845022496961}{1152921504606846976000000000000000000000000}$$