Solve 1+20-5*7/3+7-2*12*2:2

$$1 + 20 - 5 \times 7 / 3 + 7 - 2 \times 12 \cdot 2 : 2$$

Evaluate

$$-\frac{23}{3}\approx -7.666666667$$

Solution Steps

Add 1 and 20 to get 21.

$$21-5\times \frac{7}{3}+7-\frac{2\times 12\times 2}{2}$$

Express 5\times \frac{7}{3} as a single fraction.

$$21-\frac{5\times 7}{3}+7-\frac{2\times 12\times 2}{2}$$

Multiply 5 and 7 to get 35.

$$21-\frac{35}{3}+7-\frac{2\times 12\times 2}{2}$$

Convert 21 to fraction \frac{63}{3}.

$$\frac{63}{3}-\frac{35}{3}+7-\frac{2\times 12\times 2}{2}$$

Since \frac{63}{3} and \frac{35}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{63-35}{3}+7-\frac{2\times 12\times 2}{2}$$

Subtract 35 from 63 to get 28.

$$\frac{28}{3}+7-\frac{2\times 12\times 2}{2}$$

Convert 7 to fraction \frac{21}{3}.

$$\frac{28}{3}+\frac{21}{3}-\frac{2\times 12\times 2}{2}$$

Since \frac{28}{3} and \frac{21}{3} have the same denominator, add them by adding their numerators.

$$\frac{28+21}{3}-\frac{2\times 12\times 2}{2}$$

Add 28 and 21 to get 49.

$$\frac{49}{3}-\frac{2\times 12\times 2}{2}$$

Cancel out 2 and 2.

$$\frac{49}{3}-12\times 2$$

Multiply 12 and 2 to get 24.

$$\frac{49}{3}-24$$

Convert 24 to fraction \frac{72}{3}.

$$\frac{49}{3}-\frac{72}{3}$$

Since \frac{49}{3} and \frac{72}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-72}{3}$$

Subtract 72 from 49 to get -23.

$$-\frac{23}{3}$$

Factor

$$-\frac{23}{3} = -7\frac{2}{3} = -7.666666666666667$$