Solve 1+20:5*7/3*7-2*12/2=?

$$1 + 20 : 5 \times 7 / 3 * 7 - 2 \times 12 / 2 = ?$$

Evaluate

$$\frac{163}{3}\approx 54.333333333$$

Solution Steps

Divide 20 by 5 to get 4.

$$1+4\times \frac{7}{3}\times 7-2\times \frac{12}{2}$$

Express 4\times \frac{7}{3} as a single fraction.

$$1+\frac{4\times 7}{3}\times 7-2\times \frac{12}{2}$$

Multiply 4 and 7 to get 28.

$$1+\frac{28}{3}\times 7-2\times \frac{12}{2}$$

Express \frac{28}{3}\times 7 as a single fraction.

$$1+\frac{28\times 7}{3}-2\times \frac{12}{2}$$

Multiply 28 and 7 to get 196.

$$1+\frac{196}{3}-2\times \frac{12}{2}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{3}{3}+\frac{196}{3}-2\times \frac{12}{2}$$

Since \frac{3}{3} and \frac{196}{3} have the same denominator, add them by adding their numerators.

$$\frac{3+196}{3}-2\times \frac{12}{2}$$

Add 3 and 196 to get 199.

$$\frac{199}{3}-2\times \frac{12}{2}$$

Divide 12 by 2 to get 6.

$$\frac{199}{3}-2\times 6$$

Multiply 2 and 6 to get 12.

$$\frac{199}{3}-12$$

Convert 12 to fraction \frac{36}{3}.

$$\frac{199}{3}-\frac{36}{3}$$

Since \frac{199}{3} and \frac{36}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{199-36}{3}$$

Subtract 36 from 199 to get 163.

$$\frac{163}{3}$$

Factor

$$\frac{163}{3} = 54\frac{1}{3} = 54.333333333333336$$