Solve 1+2y=4^2+lambda^1

$$1 + 2 y = 4 ^ { 2 } + \lambda ^ { 1 }$$

Solve for y

$$y=\frac{\lambda +15}{2}$$

Steps for Solving Linear Equation

Calculate 4 to the power of 2 and get 16.

$$1+2y=16+\lambda ^{1}$$

Calculate \lambda to the power of 1 and get \lambda .

$$1+2y=16+\lambda$$

Subtract 1 from both sides.

$$2y=16+\lambda -1$$

Subtract 1 from 16 to get 15.

$$2y=15+\lambda$$

The equation is in standard form.

$$2y=\lambda +15$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{\lambda +15}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{\lambda +15}{2}$$

Solve for λ

$$\lambda =2y-15$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$1+2y=16+\lambda ^{1}$$

Calculate \lambda to the power of 1 and get \lambda .

$$1+2y=16+\lambda$$

Swap sides so that all variable terms are on the left hand side.

$$16+\lambda =1+2y$$

Subtract 16 from both sides.

$$\lambda =1+2y-16$$

Subtract 16 from 1 to get -15.

$$\lambda =-15+2y$$