Solve 1+2(3*i)+4(1-1/2)

$$1 + 2 ( 3 \cdot i ) + 4 ( 1 - \frac { 1 } { 2 } )$$

Evaluate

$$3+6i$$

Solution Steps

Multiply 2 and 3i to get 6i.

$$1+6i+4\left(1-\frac{1}{2}\right)$$

Convert 1 to fraction \frac{2}{2}.

$$1+6i+4\left(\frac{2}{2}-\frac{1}{2}\right)$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$1+6i+4\times \frac{2-1}{2}$$

Subtract 1 from 2 to get 1.

$$1+6i+4\times \frac{1}{2}$$

Multiply 4 and \frac{1}{2} to get \frac{4}{2}.

$$1+6i+\frac{4}{2}$$

Divide 4 by 2 to get 2.

$$1+6i+2$$

Combine the real and imaginary parts.

$$1+2+6i$$

Add 1 to 2.

$$3+6i$$

Real Part

$$3$$

Solution Steps

Multiply 2 and 3i to get 6i.

$$Re(1+6i+4\left(1-\frac{1}{2}\right))$$

Convert 1 to fraction \frac{2}{2}.

$$Re(1+6i+4\left(\frac{2}{2}-\frac{1}{2}\right))$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$Re(1+6i+4\times \frac{2-1}{2})$$

Subtract 1 from 2 to get 1.

$$Re(1+6i+4\times \frac{1}{2})$$

Multiply 4 and \frac{1}{2} to get \frac{4}{2}.

$$Re(1+6i+\frac{4}{2})$$

Divide 4 by 2 to get 2.

$$Re(1+6i+2)$$

Combine the real and imaginary parts in 1+6i+2.

$$Re(1+2+6i)$$

Add 1 to 2.

$$Re(3+6i)$$

The real part of 3+6i is 3.

$$3$$