Solve 1+2(-x+2)-1=-(x+3)-1

$$1 + 2 ( - x + 2 ) - 1 = - ( x + 3 ) - 1$$

Solve for x

$$x=8$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by -x+2.

$$1+2\left(-x\right)+4-1=-\left(x+3\right)-1$$

Add 1 and 4 to get 5.

$$5+2\left(-x\right)-1=-\left(x+3\right)-1$$

Subtract 1 from 5 to get 4.

$$4+2\left(-x\right)=-\left(x+3\right)-1$$

To find the opposite of x+3, find the opposite of each term.

$$4+2\left(-x\right)=-x-3-1$$

Subtract 1 from -3 to get -4.

$$4+2\left(-x\right)=-x-4$$

Add x to both sides.

$$4+2\left(-x\right)+x=-4$$

Subtract 4 from both sides.

$$2\left(-x\right)+x=-4-4$$

Subtract 4 from -4 to get -8.

$$2\left(-x\right)+x=-8$$

Multiply 2 and -1 to get -2.

$$-2x+x=-8$$

Combine -2x and x to get -x.

$$-x=-8$$

Multiply both sides by -1.

$$x=8$$