Solve 1+2^3(4*4/2)^2div35=

$$1 + 2 ^ { 3 } ( 4 \times \frac { 4 } { 2 } ) ^ { 2 } \div 35 =$$

Evaluate

$$\frac{547}{35}\approx 15.628571429$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$1+\frac{8\times \left(4\times \frac{4}{2}\right)^{2}}{35}$$

Divide 4 by 2 to get 2.

$$1+\frac{8\times \left(4\times 2\right)^{2}}{35}$$

Multiply 4 and 2 to get 8.

$$1+\frac{8\times 8^{2}}{35}$$

Calculate 8 to the power of 2 and get 64.

$$1+\frac{8\times 64}{35}$$

Multiply 8 and 64 to get 512.

$$1+\frac{512}{35}$$

Add 1 and \frac{512}{35} to get \frac{547}{35}.

$$\frac{547}{35}$$

Factor

$$\frac{547}{5 \cdot 7} = 15\frac{22}{35} = 15.628571428571428$$