Solve 1+2^3(4*4/2)^2div3.5=

$$1 + 2 ^ { 3 } ( 4 \times \frac { 4 } { 2 } ) ^ { 2 } \div 3.5 =$$

Evaluate

$$\frac{1031}{7}\approx 147.285714286$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$1+\frac{8\times \left(4\times \frac{4}{2}\right)^{2}}{3.5}$$

Divide 4 by 2 to get 2.

$$1+\frac{8\times \left(4\times 2\right)^{2}}{3.5}$$

Multiply 4 and 2 to get 8.

$$1+\frac{8\times 8^{2}}{3.5}$$

Calculate 8 to the power of 2 and get 64.

$$1+\frac{8\times 64}{3.5}$$

Multiply 8 and 64 to get 512.

$$1+\frac{512}{3.5}$$

Expand \frac{512}{3.5} by multiplying both numerator and the denominator by 10.

$$1+\frac{5120}{35}$$

Reduce the fraction \frac{5120}{35} to lowest terms by extracting and canceling out 5.

$$1+\frac{1024}{7}$$

Add 1 and \frac{1024}{7} to get \frac{1031}{7}.

$$\frac{1031}{7}$$

Factor

$$\frac{1031}{7} = 147\frac{2}{7} = 147.28571428571428$$