Solve 1+2^{2}+2^{3}+2^4+2^5+2^6+2^7

$$1 + 2 ^ { 2 } + 2 ^ { 3 } + 2 ^ { 4 } + 2 ^ { 5 } + 2 ^ { 6 } + 2 ^ { 7 }$$

Evaluate

$$253$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$1+4+2^{3}+2^{4}+2^{5}+2^{6}+2^{7}$$

Add 1 and 4 to get 5.

$$5+2^{3}+2^{4}+2^{5}+2^{6}+2^{7}$$

Calculate 2 to the power of 3 and get 8.

$$5+8+2^{4}+2^{5}+2^{6}+2^{7}$$

Add 5 and 8 to get 13.

$$13+2^{4}+2^{5}+2^{6}+2^{7}$$

Calculate 2 to the power of 4 and get 16.

$$13+16+2^{5}+2^{6}+2^{7}$$

Add 13 and 16 to get 29.

$$29+2^{5}+2^{6}+2^{7}$$

Calculate 2 to the power of 5 and get 32.

$$29+32+2^{6}+2^{7}$$

Add 29 and 32 to get 61.

$$61+2^{6}+2^{7}$$

Calculate 2 to the power of 6 and get 64.

$$61+64+2^{7}$$

Add 61 and 64 to get 125.

$$125+2^{7}$$

Calculate 2 to the power of 7 and get 128.

$$125+128$$

Add 125 and 128 to get 253.

$$253$$

Factor

$$11\times 23$$