Solve 1+(3*4)div(3+4*9)

$$1 + ( 3 \cdot 4 ) \div ( 3 + 4 \cdot 9 )$$

Evaluate

$$\frac{17}{13}\approx 1.307692308$$

Solution Steps

Multiply 3 and 4 to get 12.

$$1+\frac{12}{3+4\times 9}$$

Multiply 4 and 9 to get 36.

$$1+\frac{12}{3+36}$$

Add 3 and 36 to get 39.

$$1+\frac{12}{39}$$

Reduce the fraction \frac{12}{39} to lowest terms by extracting and canceling out 3.

$$1+\frac{4}{13}$$

Convert 1 to fraction \frac{13}{13}.

$$\frac{13}{13}+\frac{4}{13}$$

Since \frac{13}{13} and \frac{4}{13} have the same denominator, add them by adding their numerators.

$$\frac{13+4}{13}$$

Add 13 and 4 to get 17.

$$\frac{17}{13}$$

Factor

$$\frac{17}{13} = 1\frac{4}{13} = 1.3076923076923077$$