Solve 1+1/4x+4*y-x-y/4*x^2-4*y^2=

$$1 + \frac { 1 } { 4 x + 4 \cdot y } - \frac { x - y } { 4 \cdot x ^ { 2 } - 4 \cdot y ^ { 2 } } =$$

Evaluate

$$1$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{x-y}{4x^{2}-4y^{2}}.

$$1+\frac{1}{4x+4y}-\frac{x-y}{4\left(x+y\right)\left(x-y\right)}$$

Cancel out x-y in both numerator and denominator.

$$1+\frac{1}{4x+4y}-\frac{1}{4\left(x+y\right)}$$

Factor 4x+4y.

$$1+\frac{1}{4\left(x+y\right)}-\frac{1}{4\left(x+y\right)}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{4\left(x+y\right)}{4\left(x+y\right)}.

$$\frac{4\left(x+y\right)}{4\left(x+y\right)}+\frac{1}{4\left(x+y\right)}-\frac{1}{4\left(x+y\right)}$$

Since \frac{4\left(x+y\right)}{4\left(x+y\right)} and \frac{1}{4\left(x+y\right)} have the same denominator, add them by adding their numerators.

$$\frac{4\left(x+y\right)+1}{4\left(x+y\right)}-\frac{1}{4\left(x+y\right)}$$

Do the multiplications in 4\left(x+y\right)+1.

$$\frac{4x+4y+1}{4\left(x+y\right)}-\frac{1}{4\left(x+y\right)}$$

Since \frac{4x+4y+1}{4\left(x+y\right)} and \frac{1}{4\left(x+y\right)} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4x+4y+1-1}{4\left(x+y\right)}$$

Combine like terms in 4x+4y+1-1.

$$\frac{4x+4y}{4\left(x+y\right)}$$

Factor the expressions that are not already factored in \frac{4x+4y}{4\left(x+y\right)}.

$$\frac{4\left(x+y\right)}{4\left(x+y\right)}$$

Cancel out 4\left(x+y\right) in both numerator and denominator.

$$1$$

Factor

$$1$$