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\frac{\left(1\times 7+4\right)\times 4}{7\left(2\times 4+3\right)}
Divide \frac{1\times 7+4}{7} by \frac{2\times 4+3}{4} by multiplying \frac{1\times 7+4}{7} by the reciprocal of \frac{2\times 4+3}{4}.
\frac{\left(7+4\right)\times 4}{7\left(2\times 4+3\right)}
Multiply 1 and 7 to get 7.
\frac{11\times 4}{7\left(2\times 4+3\right)}
Add 7 and 4 to get 11.
\frac{44}{7\left(2\times 4+3\right)}
Multiply 11 and 4 to get 44.
\frac{44}{7\left(8+3\right)}
Multiply 2 and 4 to get 8.
\frac{44}{7\times 11}
Add 8 and 3 to get 11.
\frac{44}{77}
Multiply 7 and 11 to get 77.
\frac{4}{7}
Reduce the fraction \frac{44}{77} to lowest terms by extracting and canceling out 11.