Solve 085(x+45)*8=(x+45-35)*12

$$085(x+45) \times 8=(x+45-35) \times 12$$

Solve for x

$$x=-10$$

Steps for Solving Linear Equation

Multiply 0 and 85 to get 0.

$$0\left(x+45\right)\times 8=\left(x+45-35\right)\times 12$$

Multiply 0 and 8 to get 0.

$$0\left(x+45\right)=\left(x+45-35\right)\times 12$$

Anything times zero gives zero.

$$0=\left(x+45-35\right)\times 12$$

Subtract 35 from 45 to get 10.

$$0=\left(x+10\right)\times 12$$

Use the distributive property to multiply x+10 by 12.

$$0=12x+120$$

Swap sides so that all variable terms are on the left hand side.

$$12x+120=0$$

Subtract 120 from both sides. Anything subtracted from zero gives its negation.

$$12x=-120$$

Divide both sides by 12.

$$x=\frac{-120}{12}$$

Divide -120 by 12 to get -10.

$$x=-10$$