Solve 08left(3-xright)-1*2left(x+3*2right)=4

$$08 \left( 3-x \right) -1 \cdot 2 \left( x+3 \cdot 2 \right) = 4$$

Solve for x

$$x=-8$$

Steps for Solving Linear Equation

Multiply 0 and 8 to get 0.

$$0\left(3-x\right)-1\times 2\left(x+3\times 2\right)=4$$

Anything times zero gives zero.

$$0-1\times 2\left(x+3\times 2\right)=4$$

Multiply 1 and 2 to get 2.

$$0-2\left(x+3\times 2\right)=4$$

Multiply 3 and 2 to get 6.

$$0-2\left(x+6\right)=4$$

Use the distributive property to multiply -2 by x+6.

$$0-2x-12=4$$

Subtract 12 from 0 to get -12.

$$-12-2x=4$$

Add 12 to both sides.

$$-2x=4+12$$

Add 4 and 12 to get 16.

$$-2x=16$$

Divide both sides by -2.

$$x=\frac{16}{-2}$$

Divide 16 by -2 to get -8.

$$x=-8$$