Solve 075*21/7+3/4*73/7+75*1/7

$$075 \times 2 \frac{ 1 }{ 7 } + \frac{ 3 }{ 4 } \times 7 \frac{ 3 }{ 7 } +75 \times \frac{ 1 }{ 7 }$$

Evaluate

$$\frac{114}{7}\approx 16.285714286$$

Solution Steps

Multiply 0 and 75 to get 0.

$$0\times \frac{2\times 7+1}{7}+\frac{3}{4}\times \frac{7\times 7+3}{7}+75\times \frac{1}{7}$$

Multiply 2 and 7 to get 14.

$$0\times \frac{14+1}{7}+\frac{3}{4}\times \frac{7\times 7+3}{7}+75\times \frac{1}{7}$$

Add 14 and 1 to get 15.

$$0\times \frac{15}{7}+\frac{3}{4}\times \frac{7\times 7+3}{7}+75\times \frac{1}{7}$$

Multiply 0 and \frac{15}{7} to get 0.

$$0+\frac{3}{4}\times \frac{7\times 7+3}{7}+75\times \frac{1}{7}$$

Multiply 7 and 7 to get 49.

$$0+\frac{3}{4}\times \frac{49+3}{7}+75\times \frac{1}{7}$$

Add 49 and 3 to get 52.

$$0+\frac{3}{4}\times \frac{52}{7}+75\times \frac{1}{7}$$

Multiply \frac{3}{4} times \frac{52}{7} by multiplying numerator times numerator and denominator times denominator.

$$0+\frac{3\times 52}{4\times 7}+75\times \frac{1}{7}$$

Do the multiplications in the fraction \frac{3\times 52}{4\times 7}.

$$0+\frac{156}{28}+75\times \frac{1}{7}$$

Reduce the fraction \frac{156}{28} to lowest terms by extracting and canceling out 4.

$$0+\frac{39}{7}+75\times \frac{1}{7}$$

Add 0 and \frac{39}{7} to get \frac{39}{7}.

$$\frac{39}{7}+75\times \frac{1}{7}$$

Multiply 75 and \frac{1}{7} to get \frac{75}{7}.

$$\frac{39}{7}+\frac{75}{7}$$

Since \frac{39}{7} and \frac{75}{7} have the same denominator, add them by adding their numerators.

$$\frac{39+75}{7}$$

Add 39 and 75 to get 114.

$$\frac{114}{7}$$

Factor

$$\frac{2 \cdot 3 \cdot 19}{7} = 16\frac{2}{7} = 16.285714285714285$$