Solve 07(2-5x)-05(3x-2)=3(3-4x)

$$07(2-5x)-05(3x-2)=3(3-4x)$$

Solve for x

$$x=\frac{3}{4}=0.75$$

Steps for Solving Linear Equation

Multiply 0 and 7 to get 0.

$$0\left(2-5x\right)-0\times 5\left(3x-2\right)=3\left(3-4x\right)$$

Anything times zero gives zero.

$$0-0\times 5\left(3x-2\right)=3\left(3-4x\right)$$

Multiply 0 and 5 to get 0.

$$0-0\left(3x-2\right)=3\left(3-4x\right)$$

Anything times zero gives zero.

$$0-0=3\left(3-4x\right)$$

Subtracting 0 from itself leaves 0.

$$0=3\left(3-4x\right)$$

Use the distributive property to multiply 3 by 3-4x.

$$0=9-12x$$

Swap sides so that all variable terms are on the left hand side.

$$9-12x=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$-12x=-9$$

Divide both sides by -12.

$$x=\frac{-9}{-12}$$

Reduce the fraction \frac{-9}{-12} to lowest terms by extracting and canceling out -3.

$$x=\frac{3}{4}$$