Solve 07(-3)^2-05(-3)+02

$$07 ( - 3 ) ^ { 2 } - 05 ( - 3 ) + 02$$

Evaluate

$$0$$

Solution Steps

Multiply 0 and 7 to get 0.

$$0\left(-3\right)^{2}-0\times 5\left(-3\right)+0\times 2$$

Calculate -3 to the power of 2 and get 9.

$$0\times 9-0\times 5\left(-3\right)+0\times 2$$

Multiply 0 and 9 to get 0.

$$0-0\times 5\left(-3\right)+0\times 2$$

Multiply 0 and 5 to get 0.

$$0-0\left(-3\right)+0\times 2$$

Multiply 0 and -3 to get 0.

$$0-0+0\times 2$$

Subtracting 0 from itself leaves 0.

$$0+0\times 2$$

Multiply 0 and 2 to get 0.

$$0+0$$

Add 0 and 0 to get 0.

$$0$$

Factor

$$0$$