Solve 07+x^2:sqrt[3]{27/64}

$$07 + x ^ { 2 } : \sqrt[ 3 ] { \frac { 27 } { 64 } }$$

Evaluate

$$\frac{4x^{2}}{3}$$

Solution Steps

Multiply 0 and 7 to get 0.

$$0+\frac{x^{2}}{\sqrt[3]{\frac{27}{64}}}$$

Calculate \sqrt[3]{\frac{27}{64}} and get \frac{3}{4}.

$$0+\frac{x^{2}}{\frac{3}{4}}$$

Divide x^{2} by \frac{3}{4} by multiplying x^{2} by the reciprocal of \frac{3}{4}.

$$0+\frac{x^{2}\times 4}{3}$$

Anything plus zero gives itself.

$$\frac{x^{2}\times 4}{3}$$

Differentiate w.r.t. x

$$\frac{8x}{3}$$