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0-\frac{1}{3}x-\frac{1}{2}=\frac{1}{4}x
Multiply 0 and 5 to get 0.
-\frac{1}{2}-\frac{1}{3}x=\frac{1}{4}x
Subtract \frac{1}{2} from 0 to get -\frac{1}{2}.
-\frac{1}{2}-\frac{1}{3}x-\frac{1}{4}x=0
Subtract \frac{1}{4}x from both sides.
-\frac{1}{2}-\frac{7}{12}x=0
Combine -\frac{1}{3}x and -\frac{1}{4}x to get -\frac{7}{12}x.
-\frac{7}{12}x=\frac{1}{2}
Add \frac{1}{2} to both sides. Anything plus zero gives itself.
x=\frac{1}{2}\left(-\frac{12}{7}\right)
Multiply both sides by -\frac{12}{7}, the reciprocal of -\frac{7}{12}.
x=\frac{1\left(-12\right)}{2\times 7}
Multiply \frac{1}{2} times -\frac{12}{7} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-12}{14}
Do the multiplications in the fraction \frac{1\left(-12\right)}{2\times 7}.
x=-\frac{6}{7}
Reduce the fraction \frac{-12}{14} to lowest terms by extracting and canceling out 2.