Solve 05(38-4x)+19=4(8-05)+x

$$05(38-4x)+19=4(8-05)+x$$

Solve for x

$$x=-13$$

Steps for Solving Linear Equation

Multiply 0 and 5 to get 0.

$$0\left(38-4x\right)+19=4\left(8-0\times 5\right)+x$$

Anything times zero gives zero.

$$0+19=4\left(8-0\times 5\right)+x$$

Add 0 and 19 to get 19.

$$19=4\left(8-0\times 5\right)+x$$

Multiply 0 and 5 to get 0.

$$19=4\left(8-0\right)+x$$

Subtract 0 from 8 to get 8.

$$19=4\times 8+x$$

Multiply 4 and 8 to get 32.

$$19=32+x$$

Swap sides so that all variable terms are on the left hand side.

$$32+x=19$$

Subtract 32 from both sides.

$$x=19-32$$

Subtract 32 from 19 to get -13.

$$x=-13$$