Solve 05x^2-2x+5

$$05 x ^ { 2 } - 2 x + 5$$

Evaluate

$$5-2x$$

Solution Steps

Multiply 0 and 5 to get 0.

$$0x^{2}-2x+5$$

Anything times zero gives zero.

$$0-2x+5$$

Add 0 and 5 to get 5.

$$5-2x$$

Differentiate w.r.t. x

$$-2$$

Steps Using Derivative Rule for Sum

Multiply 0 and 5 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0x^{2}-2x+5)$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0-2x+5)$$

Add 0 and 5 to get 5.

$$\frac{\mathrm{d}}{\mathrm{d}x}(5-2x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-2x^{1-1}$$

Subtract 1 from 1.

$$-2x^{0}$$

For any term t except 0, t^{0}=1.

$$-2$$