Solve for x
x = \frac{3}{2} = 1\frac{1}{2} = 1.5
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0x^{2}+8x-12=0
Multiply 0 and 5 to get 0.
0+8x-12=0
Anything times zero gives zero.
-12+8x=0
Subtract 12 from 0 to get -12.
8x=12
Add 12 to both sides. Anything plus zero gives itself.
x=\frac{12}{8}
Divide both sides by 8.
x=\frac{3}{2}
Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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