Solve 05*sqrt{12}*sqrt{6}*sqrt{2}+02

$$05 \cdot \sqrt { 12 } \cdot \sqrt { 6 } \cdot \sqrt { 2 } + 02$$

Evaluate

$$0$$

Solution Steps

Multiply 0 and 5 to get 0. Multiply 0 and 2 to get 0.

$$0\sqrt{12}\sqrt{6}\sqrt{2}+0$$

Factor 12=6\times 2. Rewrite the square root of the product \sqrt{6\times 2} as the product of square roots \sqrt{6}\sqrt{2}.

$$0\sqrt{6}\sqrt{2}\sqrt{6}\sqrt{2}+0$$

Multiply \sqrt{6} and \sqrt{6} to get 6.

$$0\times 6\sqrt{2}\sqrt{2}+0$$

Multiply \sqrt{2} and \sqrt{2} to get 2.

$$0\times 6\times 2+0$$

Multiply 0 and 6 to get 0.

$$0\times 2+0$$

Multiply 0 and 2 to get 0.

$$0+0$$

Add 0 and 0 to get 0.

$$0$$

Factor

$$0$$