Solve 025x+10x47

$$025x+10x47$$

Evaluate

$$10x_{47}$$

Solution Steps

Multiply 0 and 25 to get 0.

$$0x+10x_{47}$$

Anything times zero gives zero.

$$0+10x_{47}$$

Anything plus zero gives itself.

$$10x_{47}$$

Differentiate w.r.t. x_47

$$10$$

Steps Using Definition of a Derivative

Multiply 0 and 25 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x_{47}}(0x+10x_{47})$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x_{47}}(0+10x_{47})$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x_{47}}(10x_{47})$$

The derivative of ax^{n} is nax^{n-1}.

$$10x_{47}^{1-1}$$

Subtract 1 from 1.

$$10x_{47}^{0}$$

For any term t except 0, t^{0}=1.

$$10\times 1$$

For any term t, t\times 1=t and 1t=t.

$$10$$