Solve 025*(-2)^-2div16^-1-(pi-3)^0

$$025 \times ( - 2 ) ^ { - 2 } \div 16 ^ { - 1 } - ( \pi - 3 ) ^ { 0 }$$

Evaluate

$$-1$$

Solution Steps

Multiply 0 and 25 to get 0.

$$\frac{0\left(-2\right)^{-2}}{16^{-1}}-\left(\pi -3\right)^{0}$$

Calculate -2 to the power of -2 and get \frac{1}{4}.

$$\frac{0\times \frac{1}{4}}{16^{-1}}-\left(\pi -3\right)^{0}$$

Multiply 0 and \frac{1}{4} to get 0.

$$\frac{0}{16^{-1}}-\left(\pi -3\right)^{0}$$

Calculate 16 to the power of -1 and get \frac{1}{16}.

$$\frac{0}{\frac{1}{16}}-\left(\pi -3\right)^{0}$$

Zero divided by any non-zero number gives zero.

$$0-\left(\pi -3\right)^{0}$$

Calculate \pi -3 to the power of 0 and get 1.

$$0-1$$

Subtract 1 from 0 to get -1.

$$-1$$

Factor

$$-1$$