Solve 01m^2-0.16n^2

$$01 m ^ { 2 } - 0.16 n ^ { 2 }$$

Evaluate

$$-\frac{4n^{2}}{25}$$

Solution Steps

Multiply 0 and 1 to get 0.

$$0m^{2}-0.16n^{2}$$

Anything times zero gives zero.

$$0-0.16n^{2}$$

Anything plus zero gives itself.

$$-0.16n^{2}$$

Differentiate w.r.t. n

$$-\frac{8n}{25}$$

Steps Using Definition of a Derivative

Multiply 0 and 1 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}n}(0m^{2}-0.16n^{2})$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}n}(0-0.16n^{2})$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}n}(-0.16n^{2})$$

The derivative of ax^{n} is nax^{n-1}.

$$2\left(-0.16\right)n^{2-1}$$

Multiply 2 times -0.16.

$$-0.32n^{2-1}$$

Subtract 1 from 2.

$$-0.32n^{1}$$

For any term t, t^{1}=t.

$$-0.32n$$