Solve 009(x+30)=[03(x+30)]^2/x+50

$$009 ( x + 30 ) = \frac { [ 03 ( x + 30 ) ] ^ { 2 } } { x + 50 }$$

Solve for x

$$x\neq -50$$

Solution Steps

Variable x cannot be equal to -50 since division by zero is not defined. Multiply both sides of the equation by x+50.

$$0\times 0\times 9\left(x+30\right)\left(x+50\right)=\left(0\times 3\left(x+30\right)\right)^{2}$$

Multiply 0 and 0 to get 0.

$$0\times 9\left(x+30\right)\left(x+50\right)=\left(0\times 3\left(x+30\right)\right)^{2}$$

Multiply 0 and 9 to get 0.

$$0\left(x+30\right)\left(x+50\right)=\left(0\times 3\left(x+30\right)\right)^{2}$$

Anything times zero gives zero.

$$0=\left(0\times 3\left(x+30\right)\right)^{2}$$

Multiply 0 and 3 to get 0.

$$0=\left(0\left(x+30\right)\right)^{2}$$

Anything times zero gives zero.

$$0=0^{2}$$

Calculate 0 to the power of 2 and get 0.

$$0=0$$

Compare 0 and 0.

$$\text{true}$$

This is true for any x.

$$x\in \mathrm{R}$$

Variable x cannot be equal to -50.

$$x\in \mathrm{R}\setminus -50$$