Solve 00x^2+y^2-5

$$00 x ^ { 2 } + y ^ { 2 } - 5$$

Evaluate

$$y^{2}-5$$

Solution Steps

Multiply 0 and 0 to get 0.

$$0x^{2}+y^{2}-5$$

Anything times zero gives zero.

$$0+y^{2}-5$$

Subtract 5 from 0 to get -5.

$$-5+y^{2}$$

Differentiate w.r.t. y

$$2y$$

Steps Using Derivative Rule for Sum

Multiply 0 and 0 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}y}(0x^{2}+y^{2}-5)$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}y}(0+y^{2}-5)$$

Subtract 5 from 0 to get -5.

$$\frac{\mathrm{d}}{\mathrm{d}y}(-5+y^{2})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2y^{2-1}$$

Subtract 1 from 2.

$$2y^{1}$$

For any term t, t^{1}=t.

$$2y$$