Solve 00q*(1+(15%/365))(365*1)=

$$00 q \times ( 1 + ( 15 \% / 365 ) ) ( 365 \times 1 ) =$$

Evaluate

$$0$$

Solution Steps

Multiply 0 and 0 to get 0.

$$0q\left(1+\frac{\frac{15}{100}}{365}\right)\times 365\times 1$$

Express \frac{\frac{15}{100}}{365} as a single fraction.

$$0q\left(1+\frac{15}{100\times 365}\right)\times 365\times 1$$

Multiply 100 and 365 to get 36500.

$$0q\left(1+\frac{15}{36500}\right)\times 365\times 1$$

Reduce the fraction \frac{15}{36500} to lowest terms by extracting and canceling out 5.

$$0q\left(1+\frac{3}{7300}\right)\times 365\times 1$$

Convert 1 to fraction \frac{7300}{7300}.

$$0q\left(\frac{7300}{7300}+\frac{3}{7300}\right)\times 365\times 1$$

Since \frac{7300}{7300} and \frac{3}{7300} have the same denominator, add them by adding their numerators.

$$0q\times \frac{7300+3}{7300}\times 365\times 1$$

Add 7300 and 3 to get 7303.

$$0q\times \frac{7303}{7300}\times 365\times 1$$

Multiply 0 and \frac{7303}{7300} to get 0.

$$0q\times 365\times 1$$

Multiply 0 and 365 to get 0.

$$0q\times 1$$

Multiply 0 and 1 to get 0.

$$0q$$

Anything times zero gives zero.

$$0$$

Factor

$$0$$