Solve for x
x\leq 100
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8x+300-6x\leq \frac{400}{0.8}
Divide both sides by 0.8. Since 0.8 is positive, the inequality direction remains the same.
8x+300-6x\leq \frac{4000}{8}
Expand \frac{400}{0.8} by multiplying both numerator and the denominator by 10.
8x+300-6x\leq 500
Divide 4000 by 8 to get 500.
2x+300\leq 500
Combine 8x and -6x to get 2x.
2x\leq 500-300
Subtract 300 from both sides.
2x\leq 200
Subtract 300 from 500 to get 200.
x\leq \frac{200}{2}
Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.
x\leq 100
Divide 200 by 2 to get 100.
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